Answer
Real numbers greater than 3.
Work Step by Step
$\frac{1}{\sqrt {x-3}}$
The square root of a negative has no solution in the set of the real numbers. Also, the denominator must be different from 0. It is necessary that:
$x-3\gt0$
$x\gt3$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.5 - Rational Expressions - Exercises - Page 48: 15
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