## Algebra and Trigonometry 10th Edition

Published by Cengage Learning

# Prerequisites - P.5 - Rational Expressions - Exercises - Page 48: 15

#### Answer

Real numbers greater than 3.

#### Work Step by Step

$\frac{1}{\sqrt {x-3}}$ The square root of a negative has no solution in the set of the real numbers. Also, the denominator must be different from 0. It is necessary that: $x-3\gt0$ $x\gt3$

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