Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - P.3 - Polynomials and Special Products - Exercises - Page 31: 64

Answer

$9t^4-10t^3-5t^2-4t+1$

Work Step by Step

Subtracting $(-7t^4+5t^2-1)$ from $2t^4-10t^3-4t$: $2t^4-10t^3-4t-(-7t^4+5t^2-1)$ $=2t^4-10t^3-4t+7t^4-5t^2+1$ $=9t^4-10t^3-5t^2-4t+1$
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