Answer
$x^2-6xy+9y^2-z^2$
Work Step by Step
Using the special product of sum and difference of same terms
$(u+v)(u-v)=u^2-v^2$,
$[(x-3y)+z][(x-3y)-z]$
$=(x-3y)^2-z^2$
$=x^2-6xy+9y^2-z^2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.3 - Polynomials and Special Products - Exercises - Page 31: 60
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