Answer
$x^3-6x^2+12x-8$
Work Step by Step
Let's use the concept of cubing a binomial given by, $$(x-y)^3=x^3-3x^2y+3xy^2-y^3$$Hence,
$\begin{align}(x-2)^3&=(x)^3-3(x)^2(2)+3(x)(2)^2-2^3\\&=x^3-6x^2+12x-8\end{align}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.3 - Polynomials and Special Products - Exercises - Page 31: 48
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