Answer
$x^2-6x+9+2xy-6y+y^2$
Work Step by Step
Using the special product of a binomial formula
$(u+v)^2=u^2+2uv+v^2$,
$[(x-3)+y]^2$
$=(x-3)^2+2(x-3)y+y^2$
$=x^2-6x+9+2xy-6y+y^2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.3 - Polynomials and Special Products - Exercises - Page 31: 57
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