## Algebra and Trigonometry 10th Edition

$x=0,-2, +2$ and $y=8$
We have: $2x^2 =x^4 -2x^2$ Re-write as: $x^4 -2x^2-2x^2=0$ $\implies x^2 (x^2-4)=0$ We get: $x^2 (x-2)(x+2)=0$ Thus, $x=0,-2, +2$ We will plug the value of $x$ into the expression of $y$ to find the value of $y$. So, $y=2(2)^2=8$ Therefore, $x=0,-2, +2$ and $y=8$