## Algebra and Trigonometry 10th Edition

$x=-1;y=\dfrac{-2}{3}$
We need to isolate $x$ in the second equation. $x=-9y-7$ Now, plug the value of $x$ into the first equation. $10(-9y-7)+6y+14=0 \implies -84y-56=0$ We get: $y=-\dfrac{2}{3}$ We will plug the value of $y$ into the expression of $x$ to find the value of $x$. $x=-9(-\dfrac{2}{3})-7=0=-1$ Thus, $x=-1;y=\dfrac{-2}{3}$