Algebra and Trigonometry 10th Edition

$x=\dfrac{3}{2}; y=5$
First, we isolate y: $y=4x-1$ Now, plug the value of $y$ into the second equation. $8x+4x-1-17=0 \implies 12x-18=0$ We get: $x=\dfrac{3}{2}$ Now, we find y: $y=4(3/2)-1=5$ Thus, $x=\dfrac{3}{2}; y=5$