Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 9 - Review Exercises - Page 691: 5



Work Step by Step

We need to isolate $y$ in the first equation. $y=-0.5x+0.75$ Now, plug the value of $y$ into the second equation. $1.25x-4.5 (-0.5x+0.75) =-2.5$ We get: $x=.25$ We will plug the value of $x$ into the expression of $y$ to find the value of $y$. $y=-0.5(0.25)+0.75=0.625$ Thus, $x=0.25;y=0.625$
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