## Algebra and Trigonometry 10th Edition

$x=5,2$ and $y=2,-1$
We need to rearrange the given equations as follows: $y+3 =y^2+1 \implies y^2-y-2 =0$ $\implies (y-2)(y+1)=0$ We get: $y=2,-1$ Now, we will plug the values of $y$ into the expression of $x$ to find the other unknown. When $y=2; x=2+3=5$ When $y=-1; x=-1+3=2$ Therefore, $x=5,2$ and $y=2,-1$