Chapter 9 - 9.2 - Two-Variable Linear Systems - 9.2 Exercises - Page 646: 23

$(101,96)$

Multiplying equation 1 by -30 and equation 2 by 20, we get: $-6x+15y=834$ and $6x+8y=1374$ Adding both equations, we get $23y=2208$ and thus $y=96$ (Elimination) Substituting the value of y in equation 1: $-16x+5\times 96=834$ This becomes $ 2x-480=−278$ and $x=(480-278)/2=\frac{202}{2}=101$ Thus, we get $(101,96)$ as a solution.