Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 9 - 9.2 - Two-Variable Linear Systems - 9.2 Exercises - Page 646: 16



Work Step by Step

Multiplying equation 1 by 2, we get: $2x+10y=20$ and $3x-10y=-5$ Adding both equations, we get $5x=15$ and thus $x=3$ (Elimination) Substituting the value of x in equation 1: $2\times 3 + 10y=20$ This becomes $10y=20-6=14$ and $y=\frac{7}{5}$ Thus, we get $(3,\frac{7}{5})$ as a solution.
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