Chapter 9 - 9.2 - Two-Variable Linear Systems - 9.2 Exercises - Page 646: 20

$(-17,5)$

Multiplying equation 2 by 3, and equation 1 by 2, we get: $6x+22y=8$ and $-6x-15y=27$ Adding both equations, we get $7y=35$ and thus $y=5$ (Elimination) Substituting the value of y in equation 1: $6x+110=8$ This becomes $6x=8-110=-102$ and $x=-17$ Thus, we get $(-17,5)$ as a solution.