Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 9 - 9.2 - Two-Variable Linear Systems - 9.2 Exercises - Page 646: 22



Work Step by Step

Multiplying equation 1 by -5 and equation 2 by 2, we get: $-10x-25y=-40$ and $10x+16y=20$ Adding both equations, we get $-9y=-20$ and thus $y=\frac{20}{9}$ (Elimination) Substituting the value of x in original equation 1: $2x+5\times \frac{20}{9} =8$ This becomes $2x=8-\frac{100}{9}=\frac{-28}{9}$ and $x=\frac{-14}{9}$ Thus, we get $(\frac{-14}{9},\frac{20}{9})$ as a solution.
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