## Algebra and Trigonometry 10th Edition

C = $103^{o}$ a = 0.82 b = 0.71
Note: The Law of Sines is: $\frac{a}{sin(A)}$ = $\frac{b}{sin(B)}$ = $\frac{c}{sin(C)}$ To solve the triangle, we need to find a, b, and C. Finding C: Since we are given 2 other angles, we can use the fact that a triangle has angles that add to $180^{o}$. 180 - 42 - 35 = 103 Therefore, C = $103^{o}$ Finding a: We can use the Law of Sines. $\frac{a}{sin(42^{o})} = \frac{1.2}{sin(103^{o})}$ Therefore, a = 0.82 Finding b: We can use the Law of Sines. $\frac{b}{sin(35^{o})} = \frac{1.2}{sin(103^{o})}$ Therefore, b = 0.71 In total: C = $103^{o}$ a = 0.82 b = 0.71