## Algebra and Trigonometry 10th Edition

$\phi = 135^{o}$ d = 5.69 c = 12.07
The following are the given values: a = 5 b = 8 $\theta = 45^{o}$ Finding $\phi$: A parallelogram has a total of $360^{o}$. Using that information: 45 + 45 = 90 360 - 90 = 270 $\frac{270}{2} = 135^{o}$ $\phi = 135^{o}$ Using the Law of Cosines, we can find d: $d^{2} = 5^{2} + 8^{2} - 2(5)(8)cos(45^{o})$ d = 5.69 Using the Law of Cosines, we can find c: $c^{2} = 5^{2} + 8^{2} - 2(5)(8)cos(135^{o})$ c = 12.07 In total, the values are: $\phi = 135^{o}$ d = 5.69 c = 12.07