## Algebra and Trigonometry 10th Edition

a = 23.38 B = $29.44^{o}$ C = $100.56^{o}$
Note: The Standard Form of the Law of Cosines is: $a^{2} = b^{2} + c^{2} - 2bc(cosA)$ Note: The Alternative Form of the Law of Cosines is: $cosA = \frac{b^{2} + c^{2} - a^{2}}{2bc}$ To solve the triangle, we need to find a, B, and C. We can use the Standard and Alternative Form of the Law of Cosines to solve the triangle. Finding a: $a^{2} = 15^{2} + 30^{2} - 2(15)(30)cos(50^{o})$ a = 23.38 Finding B: $cosB = \frac{23.38^{2} + 30^{2} - 15^{2}}{2(23.38)(30)}$ B = $29.44^{o}$ Finding C: $cosC = \frac{23.38^{2} + 15^{2} - 30^{2}}{2(23.38)(15)}$ C = $100.56^{o}$ In Total: a = 23.38 B = $29.44^{o}$ C = $100.56^{o}$