## Algebra and Trigonometry 10th Edition

Note: The Law of Sines is: $\frac{a}{sin(A)}$ = $\frac{b}{sin(B)}$ = $\frac{c}{sin(C)}$ To solve the triangle, we need to find B, C, and c. Finding B: We can use the Law of Sines. $\frac{4}{sin(24^{o})} = \frac{18}{sin(B^{o})}$ Therefore, sin(B) = $1.83$ 1.83 is outside of the domain of sine; therefore, there is no triangle.