## Algebra and Trigonometry 10th Edition

$\theta = 60^{o}$ d = 31.22 c = 52.20
The following are the given values: a = 25 b = 35 $\phi = 120^{o}$ Finding $\theta$: A parallelogram has a total of $360^{o}$. Using that information: 120 + 120 = 240 360 - 240 = 120 $\frac{120}{2} = 60^{o}$ $\theta = 60^{o}$ Using the Law of Cosines, we can find d: $d^{2} = 25^{2} + 35^{2} - 2(25)(35)cos(60^{o})$ d = 31.22 Using the Law of Cosines, we can find c: $c^{2} = 25^{2} + 35^{2} - 2(25)(35)cos(120^{o})$ c = 52.20 $\theta = 60^{o}$ d = 31.22 c = 52.20