Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - Chapter Test - Page 554: 8


$\dfrac{\tan x+\tan {\pi/2}}{1-\tan x \tan (\pi/2)}=-\cot x$ Verified

Work Step by Step

$\dfrac{\tan x+\tan {\pi/2}}{1-\tan x \tan (\pi/2)}=\dfrac{1+\dfrac{\tan x}{\tan {\pi/2}}}{1/\tan {\pi/2} -\tan x}$ or, $=\dfrac{\tan x \cot (\pi/2)+1}{\cot (\pi/2)-\tan x}$ or, $=\dfrac{-1}{\tan x}$ or, $=-\cot x$
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