Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - Chapter Test - Page 554: 4


$\csc \theta \sec \theta$

Work Step by Step

We know that $1+\tan^2 x=\sec^2 x $ $\dfrac{\cos \theta}{\sin \theta}+\dfrac{\sin \theta}{\cos \theta}=\dfrac{\cos^2 \theta+\sin^2 \theta}{\sin \theta \cos \theta}$ or, $=\dfrac{1}{\sin \theta \cos \theta}$ or, $=\csc \theta \sec \theta$
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