## Algebra and Trigonometry 10th Edition

x = $\frac{\pi}{6}$, $\frac{11\pi}{6}$, $\frac{5\pi}{6}$, $\frac{7\pi}{6}$
$4cos^{2}(x) - 3 = 0$ We can manipulate the equation as follows: $4cos^{2}(x) = 3$ $cos^{2}(x) = \frac{3}{4}$ $cos(x) = \sqrt \frac{3}{4}$ = $\frac{\sqrt 3}{2}$ This gives 4 possible solutions: x = $\frac{\pi}{6}$, $\frac{11\pi}{6}$, $\frac{5\pi}{6}$, $\frac{7\pi}{6}$