## Algebra and Trigonometry 10th Edition

$x = 0, \pi, \frac{3\pi}{4}, \frac{7\pi}{4}$
$tan^{2}(x) + tan(x) = 0$ Factor the expression: $tan(x) (tan(x) + 1) = 0$ Since it is equal to 0, it can be divided into: tan(x) = 0 and tan(x) + 1 = 0 For tan(x) = 0: x = 0, $\pi$ For tan(x) + 1 = 0: We manipulate the equation as follows: tan(x) = -1 x = $\frac{3\pi}{4}, \frac{7\pi}{4}$ The solutions are: $x = 0, \pi, \frac{3\pi}{4}, \frac{7\pi}{4}$