Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 7 - Chapter Test - Page 554: 2



Work Step by Step

We know that $\sin^2 x+\cos^2 x=1$ $\csc^2 \beta (1-\csc^2 \beta)=\csc^2 \beta \sin^2 \beta$ or, $=(\dfrac{1}{\sin^2 \beta}) \times \sin^2 \beta$ or, $\csc^2 \beta (1-\csc^2 \beta)=1$
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