## Algebra and Trigonometry 10th Edition

The identity is verified. $\frac{sec~\theta-1}{1-cos~\theta}$: red $sec~\theta$: black
Remember: $sec~\theta=\frac{1}{cos~\theta}$ So: $sec~\theta~cos~\theta=\frac{1}{cos~\theta}~cos~\theta=1$ $\frac{sec~\theta-1}{1-cos~\theta}~\frac{1+cos~\theta}{1+cos~\theta}=\frac{sec~\theta+1-1-cos~\theta}{1-cos^2\theta}=\frac{sec~\theta-cos~\theta}{sin^2\theta}~\frac{cos~\theta}{cos~\theta}=\frac{1-cos^2\theta}{sin^2\theta~cos~\theta}=\frac{sin^2\theta}{sin^2\theta~cos~\theta}=\frac{1}{cos~\theta}=sec~\theta$