## Algebra and Trigonometry 10th Edition

The trigonometric Identity is verified. $\frac{cos(\frac{\pi}{2}-x)}{sin(\frac{\pi}{2}-x)}=tan~x$
We know that: $cos(\frac{\pi}{2}-x)=sin~x$ $sin(\frac{\pi}{2}-x)=cos~x$ (Cofunction Identities, page 508) Start at the left side of the equation: $\frac{cos(\frac{\pi}{2}-x)}{sin(\frac{\pi}{2}-x)}=\frac{sin~x}{cos~x}=tan~x$