Answer
The identity is verified.
$(1+sin~y)[1+sin(-y)]=cos^2y$
Work Step by Step
$sin^2y+cos^2y=1$
$cos^2y=1-sin^2y$
$(1+sin~y)[1+sin(-y)]=(1+sin~y)(1-sin~y)=1^2-sin^2y=cos^2y$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 7 - 7.2 - Verifying Trigonometric Identities - 7.2 Exercises - Page 520: 39
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