## Algebra and Trigonometry 10th Edition

The trigonometric Identity is verified. $sin~t~csc(\frac{\pi}{2}-t)=tan~t$
We know that: $csc(\frac{\pi}{2}-t)=sec~t~~$ (Cofunction Identity, page 508) $sec~t=\frac{1}{cos~t}$ Start at the left side of the equation: $sin~t~csc(\frac{\pi}{2}-t)=sin~t~sec~t=sin~t~\frac{1}{cos~t}=\frac{sin~t}{cos~t}=tan~t$