## Algebra and Trigonometry 10th Edition

Published by Cengage Learning

# Chapter 6 - 6.3 - Trigonometric Functions of Any Angle - 6.3 Exercises - Page 454: 93

#### Answer

($\frac{\sqrt 2}{2}$,$\frac{\sqrt 2}{2}$) cos($\frac{\pi}{4}$) = $\frac{\sqrt 2}{2}$ sin($\frac{\pi}{4}$) = $\frac{\sqrt 2}{2}$ tan($\frac{\pi}{4}$) = 1

#### Work Step by Step

Using the unit circle when t = $\frac{\pi}{4}$, The (x,y) point is ($\frac{\sqrt 2}{2}$,$\frac{\sqrt 2}{2}$) Using the coordinate points: cos($\frac{\pi}{4}$) = $\frac{\sqrt 2}{2}$ sin($\frac{\pi}{4}$) = $\frac{\sqrt 2}{2}$ tan($\frac{\pi}{4}$) = 1

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