## Algebra and Trigonometry 10th Edition

($\frac{\sqrt 2}{2}$,$\frac{\sqrt 2}{2}$) cos($\frac{\pi}{4}$) = $\frac{\sqrt 2}{2}$ sin($\frac{\pi}{4}$) = $\frac{\sqrt 2}{2}$ tan($\frac{\pi}{4}$) = 1
Using the unit circle when t = $\frac{\pi}{4}$, The (x,y) point is ($\frac{\sqrt 2}{2}$,$\frac{\sqrt 2}{2}$) Using the coordinate points: cos($\frac{\pi}{4}$) = $\frac{\sqrt 2}{2}$ sin($\frac{\pi}{4}$) = $\frac{\sqrt 2}{2}$ tan($\frac{\pi}{4}$) = 1