Answer
$ \sin 300^{\circ}=-\frac{\sqrt 3}{2}$,
$\cos 300^{\circ}=\frac{1}{2}$
$\tan 300^{\circ}=-\sqrt {3}$
Work Step by Step
Reference angle $\theta' =360^{\circ}-\theta$ if $\theta $ is in quadrant IV.
$\implies \theta'=360^{\circ}-300^{\circ}=60^{\circ}$
Sine is negative, cosine is positive and tangent is negative in quadrant IV.
$\implies \sin 300^{\circ}=-\sin 60^{\circ}=-\frac{\sqrt 3}{2}$,
$\cos 300^{\circ}=+\cos 60^{\circ}=\frac{1}{2}$
$\tan 300^{\circ}=-\tan 60^{\circ}=-\sqrt {3}$
