Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 6 - 6.3 - Trigonometric Functions of Any Angle - 6.3 Exercises - Page 454: 66

Answer

$csc\theta = \sqrt 10$

Work Step by Step

Note: $sin\theta = \frac{opp}{hyp}$ $cos\theta = \frac{adj}{hyp}$ $tan\theta = \frac{opp}{adj}$ $cot\theta = -3$ The equivalent is: $tan\theta = \frac{-1}{3}$ We must find the Hypotenuse: $\sqrt {1^{2}+3^{2}} = \sqrt 10$ We can then solve for $csc\theta$: $sin\theta = \frac{1}{\sqrt 10}$ Therefore, $csc\theta = \sqrt 10$
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