## Algebra and Trigonometry 10th Edition

$3: 00 \ am$
$t=-10 \ln \dfrac{T-70}{98.6-70}$ We are given the model: $T=85.7$ $t=-10 \ln \dfrac{85.7-70}{98.6-70}$ or, $t=-10 \ln \dfrac{15.7}{28.6}$ or, $t \approx 6$ The person died 6 hours before 9:00 am. Our answer is: 3: 00 am