Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.5 - Exponential and Logarithmic Models - 5.5 Exercises - Page 408: 54


$6.31 \times 10^{-4}$

Work Step by Step

We are given the model: $pH =- \log [H^{+}]$ Therefore, $3.2=- \log [H^{+}]$ Or, $-3.2= \log [H^{+}]$ or, $10^{-3.2}=[H^{+}]$ Therefore, $[H^{+}]=6.31 \times 10^{-4}$
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