Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 5 - 5.5 - Exponential and Logarithmic Models - 5.5 Exercises - Page 408: 51

Answer

$4.64$

Work Step by Step

We are given the model: $pH =- \log H^{+}$ Plug in the data: Therefore, $pH =- \log 2.3 \times 10^{-5}$ Or, $pH =- \log 2.3 \times 10^{-5} \approx 4.64$
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