## Algebra and Trigonometry 10th Edition

$10^{5.1}$ times
We are given the model: $[pH]_{\ juice} =2.9$ and $[pH]_{\ water} =8.0$ $[p H]=-\log [H^{+}]$ Or, $[H^{+}]= 10^{-[p H]}$ Now, $\dfrac{[H^{+}]_{\ juice}}{[H^{+}]_{\ water}} =\dfrac{10^{-2.9}}{10^{-8}}$ or, $=10^{-2.9 -(-8) }$ or, $=10^{5.1}$ times