## Algebra and Trigonometry 10th Edition

$1.58 \times 10^{-6}$
We are given the model: $pH =- \log [H^{+}]$ Therefore, $5.8=- \log [H^{+}]$ Or, $-5.8= \log [H^{+}]$ or, $10^{-5.8}=[H^{+}]$ Therefore, $[H^{+}]=1.58 \times 10^{-6}$