Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - 2.1 - Linear Equations in Two Variables - 2.1 Exercises - Page 170: 71

Answer

$L_{1}$ and $L_{2}$ are both horizontal lines, so they are parallel.

Work Step by Step

$$L_{1}: (-6, -3), (2,-3)$$ $m_{1}=\frac{-3-(-3)}{2-(-6)}$ $m_{1}=\frac{0}{8}=0$ $$L_{2}: (3, -\frac{1}{2}), (6, -\frac{1}{2})$$ $m_{2}=\frac{-\frac{1}{2}-(-\frac{1}{2})}{6-3}$ $m_{2}=\frac{0}{3}=0$
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