Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - 2.1 - Linear Equations in Two Variables - 2.1 Exercises - Page 170: 58

Answer

$y=-3$

Work Step by Step

Given the points: $(-6,-3), (2,-3)$ We determine the slope of the line: $m=\frac{y_2-y_1}{x_2-x_1}=\frac{-3-(-3)}{2-(-6)}=0$ Now we write the line's equation: $y-(-3)=0(x-2)$ $y=-3$ The line is parallel to the $x$-axis, $3$ units below it.
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