Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 2 - 2.1 - Linear Equations in Two Variables - 2.1 Exercises - Page 170: 63

Answer

$y=-1$

Work Step by Step

$(2,-1), (\frac{1}{3}, -1)$ $y+1= \frac{-1-(-1)}{\frac{1}{3}-2}(x-2)$ $y+1=0$ $y=-1$
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