Answer
$y=-\frac{1}{3}x+\frac{4}{3}$
Work Step by Step
$(1,1), (6, -\frac{2}{3})$
$y-1=\frac{-\frac{2}{3}-1}{6-1}\times (x-1)$
$y-1=-\frac{1}{3}(x-1)$
$y-1=-\frac{1}{3}x+\frac{1}{3}$
$y=-\frac{1}{3}x+\frac{4}{3}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 2 - 2.1 - Linear Equations in Two Variables - 2.1 Exercises - Page 170: 60
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