## Algebra and Trigonometry 10th Edition

$\frac{x}{3}+\frac{y}{3}=1$
Use the intercept form of the line. $\frac{x}{a}+\frac{y}{b}=1$ (where intercepts are (a,0) and (0,b)) Put the given intercepts into the equation: $\frac{x}{c}+\frac{y}{c}=1$ x+y=c 1+2=c c=3 $\frac{x}{3}+\frac{y}{3}=1$