Answer
The identity is verified.
$_nC_{n-1}=~_nC_1$
Work Step by Step
$_nC_{n-1}=\frac{n!}{[n-(n-1)]!(n-1)!}=\frac{n!}{1!~(n-1)!}=\frac{n!}{(n-1)!~1!}=~_nC_1$
It can also be verified that: $_nC_{n-1}=~_nC_1=n$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.6 - Counting Principles - 11.6 Exercises - Page 825: 89
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