Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.6 - Counting Principles - 11.6 Exercises - Page 825: 70


9 diagonals.

Work Step by Step

We must select two vertices among six vertices. The order in which they are selected is not important. So, we have $_6C_2$ different combinations: $_6C_2=\frac{6!}{(6-2)!~2!}=\frac{6\times5\times4!}{4!~2!}=15$ But, among those 15 combinations, six are sides. $Diagonals=15-6=9$
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