Answer
$n=5$
Work Step by Step
$5·~_{n-1}P_1=~_{n}P_2$
$5~\frac{(n-1)!}{(n-1-1)!}=\frac{n!}{(n-2)!}$
$5=\frac{n!~(n-1-1)!}{(n-1)!~(n-2)!}=\frac{n(n-1)!~(n-2)!}{(n-1)!~(n-2)!}$
$5=n$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 11 - 11.6 - Counting Principles - 11.6 Exercises - Page 825: 76
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