Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.6 - Counting Principles - 11.6 Exercises - Page 825: 76



Work Step by Step

$5·~_{n-1}P_1=~_{n}P_2$ $5~\frac{(n-1)!}{(n-1-1)!}=\frac{n!}{(n-2)!}$ $5=\frac{n!~(n-1-1)!}{(n-1)!~(n-2)!}=\frac{n(n-1)!~(n-2)!}{(n-1)!~(n-2)!}$ $5=n$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.