Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.6 - Counting Principles - 11.6 Exercises - Page 825: 77



Work Step by Step

$_{n+1}P_3=4·~_{n}P_2$ $\frac{(n+1)!}{(n+1-3)!}=4~\frac{n!}{(n-2)!}$ $\frac{(n+1)!~(n-2)!}{n!~(n+1-3)!}=4$ $\frac{(n+1)n!~(n-2)!}{n!~(n-2)!}=4$ $n+1=4$ $n=3$
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