Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 11 - 11.6 - Counting Principles - 11.6 Exercises - Page 825: 81



Work Step by Step

$_{n}P_k=\frac{n!}{(n-k)!}$ Hence here $_{n}P_4=\frac{n!}{(n-4)!}=10_{n-1}P_3=10\frac{(n-1)!}{((n-1)-3)!}\\\frac{n!}{(n-4)!}=10\frac{(n-1)!}{(n-4)!}\\n(n-1)(n-2)(n-3)=10(n-1)(n-2)(n-3)\\n=10$
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