Algebra and Trigonometry 10th Edition

The reduced row-echelon form of the matrix is: $\begin{bmatrix} 1 & 5 & 0 & |0\\ 0 & 0 & 1 & |3\\ 0 & 0 & 0 & |0\\ 0 & 0 & 0 & |0\\ \end{bmatrix}$ We can write the solution as: x + 5y = 0 z = 3 We then can write the system in terms of y: x = -5y z = 3 To not use one of the variables in the system we can use a: x = -5a y = a z = 3 Where a is any real number