Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 10 - 10.1 - Matrices and Systems of Equations - 10.1 Exercises - Page 711: 78

Answer

x = -6 y = 8 z = 2

Work Step by Step

NOTE: Gauss-Jordan elimination will reduce until the matrix is in reduced row-echelon form. $\begin{bmatrix} 2 & 2 & -1 & |2\\ 1 & -3 & 1 & |-28\\ -1 & 1 & 0 & |14\\ \end{bmatrix}$ ~ $\begin{bmatrix} 2 & 2 & -1 & |2\\ 0 & 8 & -3 & |58\\ 0 & 4 & -1 & |30\\ \end{bmatrix}$ ~ $\begin{bmatrix} 2 & 2 & -1 & |2\\ 0 & 8 & -3 & |58\\ 0 & 0 & -1 & |-2\\ \end{bmatrix}$ ~ $\begin{bmatrix} 2 & 2 & -1 & |2\\ 0 & 8 & -3 & |58\\ 0 & 0 & 1 & |2\\ \end{bmatrix}$ ~ $\begin{bmatrix} 2 & 2 & 0 & |4\\ 0 & 8 & 0 & |64\\ 0 & 0 & 1 & |2\\ \end{bmatrix}$ ~ $\begin{bmatrix} 1 & 1 & 0 & |2\\ 0 & 1 & 0 & |8\\ 0 & 0 & 1 & |2\\ \end{bmatrix}$ ~ $\begin{bmatrix} 1 & 0 & 0 & |-6\\ 0 & 1 & 0 & |8\\ 0 & 0 & 1 & |2\\ \end{bmatrix}$ From reduced row-echelon form the solution is simple: x = -6 y = 8 z = 2
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