Algebra and Trigonometry 10th Edition

The reduced row-echelon form of the matrix is: $\begin{bmatrix} 1 & 0 & 0 & |0\\ 0 & 1 & 4 & |2\\ 0 & 0 & 0 & |0\\ 0 & 0 & 0 & |0\\ \end{bmatrix}$ We can write the solution as: x = 0 y + 4z = 2 We then can write the system in terms of z: x = 0 y = -4z + 2 To not use one of the basis variables we can use a: x = 0 y = -4a + 2 z = a Where a is any real number