#### Answer

x = 5a + 4
y = -3a + 2
z = a
Where a is any real number.

#### Work Step by Step

$\begin{bmatrix}
1 & 2 & 1 & |8\\
3 & 7 & 6 & |26\\
\end{bmatrix}$ ~ $\begin{bmatrix}
1 & 2 & 1 & |8\\
0 & 1 & 3 & |2\\
\end{bmatrix}$ ~ $\begin{bmatrix}
1 & 0 & -5 & |4\\
0 & 1 & 3 & |2\\
\end{bmatrix}$
The solution can be written as:
x - 5z = 4
y + 3z = 2
The solution can then be written in terms of z:
x = 5z + 4
y = -3z + 2
Then replace z with "a" in order to avoid using a system variable in the answer:
x = 5a + 4
y = -3a + 2
z = a
Where "a" is any real number.